This module implements some common generic algorithms on openArrays.
Basic usage
Example:
import std/algorithm type People = tuple year: int name: string var a: seq[People] a.add((2000, "John")) a.add((2005, "Marie")) a.add((2010, "Jane")) # Sorting with default system.cmp a.sort() assert a == @[(year: 2000, name: "John"), (year: 2005, name: "Marie"), (year: 2010, name: "Jane")] proc myCmp(x, y: People): int = cmp(x.name, y.name) # Sorting with custom proc a.sort(myCmp) assert a == @[(year: 2010, name: "Jane"), (year: 2000, name: "John"), (year: 2005, name: "Marie")]
See also
- sequtils module for working with the built-in seq type
- tables module for sorting tables
Procs
proc `*`(x: int; order: SortOrder): int {.inline, ...raises: [], tags: [].}
-
Flips the sign of x if order == Descending. If order == Ascending then x is returned.
x is supposed to be the result of a comparator, i.e.
< 0 for less than,
== 0 for equal,
> 0 for greater than.Example:
assert -123 * Descending == 123 assert 123 * Descending == -123 assert -123 * Ascending == -123 assert 123 * Ascending == 123
Source Edit proc binarySearch[T, K](a: openArray[T]; key: K; cmp: proc (x: T; y: K): int {.closure.}): int {. effectsOf: cmp.}
-
Binary search for key in a. Return the index of key or -1 if not found. Assumes that a is sorted according to cmp.
cmp is the comparator function to use, the expected return values are the same as those of system.cmp.
Example:
assert binarySearch(["a", "b", "c", "d"], "d", system.cmp[string]) == 3 assert binarySearch(["a", "b", "c", "d"], "c", system.cmp[string]) == 2
Source Edit proc binarySearch[T](a: openArray[T]; key: T): int
-
Binary search for key in a. Return the index of key or -1 if not found. Assumes that a is sorted.
Example:
assert binarySearch([0, 1, 2, 3, 4], 4) == 4 assert binarySearch([0, 1, 2, 3, 4], 2) == 2
Source Edit proc fill[T](a: var openArray[T]; first, last: Natural; value: T)
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Assigns value to all elements of the slice a[first..last].
If an invalid range is passed, it raises IndexDefect.
Example:
var a: array[6, int] a.fill(1, 3, 9) assert a == [0, 9, 9, 9, 0, 0] a.fill(3, 5, 7) assert a == [0, 9, 9, 7, 7, 7] doAssertRaises(IndexDefect, a.fill(1, 7, 9))
Source Edit proc fill[T](a: var openArray[T]; value: T)
-
Assigns value to all elements of the container a.
Example:
var a: array[6, int] a.fill(9) assert a == [9, 9, 9, 9, 9, 9] a.fill(4) assert a == [4, 4, 4, 4, 4, 4]
Source Edit func isSorted[T](a: openArray[T]; cmp: proc (x, y: T): int {.closure.}; order = SortOrder.Ascending): bool {.effectsOf: cmp.}
-
Checks to see whether a is already sorted in order using cmp for the comparison. The parameters are identical to sort. Requires O(n) time.
See also:
Example:
let a = [2, 3, 1, 5, 4] b = [1, 2, 3, 4, 5] c = [5, 4, 3, 2, 1] d = ["adam", "brian", "cat", "dande"] e = ["adam", "dande", "brian", "cat"] assert isSorted(a) == false assert isSorted(b) == true assert isSorted(c) == false assert isSorted(c, Descending) == true assert isSorted(d) == true assert isSorted(e) == false
Source Edit proc isSorted[T](a: openArray[T]; order = SortOrder.Ascending): bool
-
Shortcut version of isSorted that uses system.cmp[T] as the comparison function.
See also:
Example:
let a = [2, 3, 1, 5, 4] b = [1, 2, 3, 4, 5] c = [5, 4, 3, 2, 1] d = ["adam", "brian", "cat", "dande"] e = ["adam", "dande", "brian", "cat"] assert isSorted(a) == false assert isSorted(b) == true assert isSorted(c) == false assert isSorted(c, Descending) == true assert isSorted(d) == true assert isSorted(e) == false
Source Edit proc lowerBound[T, K](a: openArray[T]; key: K; cmp: proc (x: T; k: K): int {.closure.}): int {. effectsOf: cmp.}
-
Returns the index of the first element in a that is not less than (i.e. greater or equal to) key, or last if no such element is found. In other words if you have a sorted sequence and you call insert(thing, elm, lowerBound(thing, elm)) the sequence will still be sorted. Assumes that a is sorted according to cmp.
If an invalid range is passed, it raises IndexDefect.
This version uses cmp to compare the elements. The expected return values are the same as those of system.cmp.
See also:
- upperBound proc sorted by cmp in the specified order
- upperBound proc
Example:
var arr = @[1, 2, 3, 5, 6, 7, 8, 9] assert arr.lowerBound(3, system.cmp[int]) == 2 assert arr.lowerBound(4, system.cmp[int]) == 3 assert arr.lowerBound(5, system.cmp[int]) == 3 arr.insert(4, arr.lowerBound(4, system.cmp[int])) assert arr == [1, 2, 3, 4, 5, 6, 7, 8, 9]
Source Edit proc lowerBound[T](a: openArray[T]; key: T): int
-
Returns the index of the first element in a that is not less than (i.e. greater or equal to) key, or last if no such element is found. In other words if you have a sorted sequence and you call insert(thing, elm, lowerBound(thing, elm)) the sequence will still be sorted. Assumes that a is sorted.
This version uses the default comparison function cmp.
See also:
- upperBound proc sorted by cmp in the specified order
- upperBound proc
proc merge[T](result: var seq[T]; x, y: openArray[T]) {.inline.}
-
Shortcut version of merge that uses system.cmp[T] as the comparison function.
See also:
Example:
let x = [5, 10, 15, 20, 25] let y = [50, 40, 30, 20, 10].sorted var merged: seq[int] merged.merge(x, y) assert merged.isSorted assert merged == @[5, 10, 10, 15, 20, 20, 25, 30, 40, 50]
Source Edit proc merge[T](result: var seq[T]; x, y: openArray[T]; cmp: proc (x, y: T): int {.closure.}) {.effectsOf: cmp.}
-
Merges two sorted openArray. x and y are assumed to be sorted. If you do not wish to provide your own cmp, you may use system.cmp or instead call the overloaded version of merge, which uses system.cmp.Note: The original data of result is not cleared, new data is appended to result.
See also:
Example:
let x = @[1, 3, 6] let y = @[2, 3, 4] block: var merged = @[7] # new data is appended to merged sequence merged.merge(x, y, system.cmp[int]) assert merged == @[7, 1, 2, 3, 3, 4, 6] block: var merged = @[7] # if you only want new data, clear merged sequence first merged.setLen(0) merged.merge(x, y, system.cmp[int]) assert merged.isSorted assert merged == @[1, 2, 3, 3, 4, 6] import std/sugar var res: seq[(int, int)] res.merge([(1, 1)], [(1, 2)], (a, b) => a[0] - b[0]) assert res == @[(1, 1), (1, 2)] assert seq[int].default.dup(merge([1, 3], [2, 4])) == @[1, 2, 3, 4]
Source Edit proc nextPermutation[T](x: var openArray[T]): bool {.discardable.}
-
Calculates the next lexicographic permutation, directly modifying x. The result is whether a permutation happened, otherwise we have reached the last-ordered permutation.
If you start with an unsorted array/seq, the repeated permutations will not give you all permutations but stop with the last.
See also:
Example:
var v = @[0, 1, 2, 3] assert v.nextPermutation() == true assert v == @[0, 1, 3, 2] assert v.nextPermutation() == true assert v == @[0, 2, 1, 3] assert v.prevPermutation() == true assert v == @[0, 1, 3, 2] v = @[3, 2, 1, 0] assert v.nextPermutation() == false assert v == @[3, 2, 1, 0]
Source Edit proc prevPermutation[T](x: var openArray[T]): bool {.discardable.}
-
Calculates the previous lexicographic permutation, directly modifying x. The result is whether a permutation happened, otherwise we have reached the first-ordered permutation.
See also:
Example:
var v = @[0, 1, 2, 3] assert v.prevPermutation() == false assert v == @[0, 1, 2, 3] assert v.nextPermutation() == true assert v == @[0, 1, 3, 2] assert v.prevPermutation() == true assert v == @[0, 1, 2, 3]
Source Edit proc product[T](x: openArray[seq[T]]): seq[seq[T]]
-
Produces the Cartesian product of the array. Every element of the result is a combination of one element from each seq in x, with the ith element coming from x[i].Warning: complexity may explode.
Example:
assert product(@[@[1], @[2]]) == @[@[1, 2]] assert product(@[@["A", "K"], @["Q"]]) == @[@["K", "Q"], @["A", "Q"]]
Source Edit proc reverse[T](a: var openArray[T])
-
Reverses the contents of the container a.
See also:
- reversed proc reverse a slice and returns a seq[T]
- reversed proc reverse and returns a seq[T]
Example:
var a = [1, 2, 3, 4, 5, 6] a.reverse() assert a == [6, 5, 4, 3, 2, 1] a.reverse() assert a == [1, 2, 3, 4, 5, 6]
Source Edit proc reverse[T](a: var openArray[T]; first, last: Natural)
-
Reverses the slice a[first..last].
If an invalid range is passed, it raises IndexDefect.
See also:
- reversed proc reverse a slice and returns a seq[T]
- reversed proc reverse and returns a seq[T]
Example:
var a = [1, 2, 3, 4, 5, 6] a.reverse(1, 3) assert a == [1, 4, 3, 2, 5, 6] a.reverse(1, 3) assert a == [1, 2, 3, 4, 5, 6] doAssertRaises(IndexDefect, a.reverse(1, 7))
Source Edit proc reversed[T](a: openArray[T]): seq[T] {.inline.}
-
Returns the elements of a in reverse order.
See also:
Example:
assert [10, 11, 12].reversed == @[12, 11, 10] assert seq[string].default.reversed == @[]
Source Edit proc reversed[T](a: openArray[T]; first: Natural; last: int): seq[T] {.inline, ...deprecated: "use: `reversed(toOpenArray(a, first, last))`".}
- Source Edit
proc rotatedLeft[T](arg: openArray[T]; dist: int): seq[T]
-
Same as rotateLeft, just with the difference that it does not modify the argument. It creates a new seq instead.
See also:
- rotateLeft proc for the in-place version of this proc
- rotatedLeft proc for a version which rotates a range
Example:
var a = @[1, 2, 3, 4, 5] a = rotatedLeft(a, 2) assert a == @[3, 4, 5, 1, 2] a = rotatedLeft(a, 4) assert a == @[2, 3, 4, 5, 1] a = rotatedLeft(a, -6) assert a == @[1, 2, 3, 4, 5]
Source Edit proc rotatedLeft[T](arg: openArray[T]; slice: HSlice[int, int]; dist: int): seq[ T]
-
Same as rotateLeft, just with the difference that it does not modify the argument. It creates a new seq instead.
Elements outside of slice will be left unchanged. If an invalid range (HSlice) is passed, it raises IndexDefect.
- slice
- The indices of the element range that should be rotated.
- dist
- The distance in amount of elements that the data should be rotated. Can be negative, can be any number.
See also:
- rotateLeft proc for the in-place version of this proc
- rotatedLeft proc for a version which rotates the whole container
Example:
var a = @[1, 2, 3, 4, 5] a = rotatedLeft(a, 1 .. 4, 3) assert a == @[1, 5, 2, 3, 4] a = rotatedLeft(a, 1 .. 3, 2) assert a == @[1, 3, 5, 2, 4] a = rotatedLeft(a, 1 .. 3, -2) assert a == @[1, 5, 2, 3, 4]
Source Edit proc rotateLeft[T](arg: var openArray[T]; dist: int): int {.discardable.}
-
Same as rotateLeft, but with default arguments for slice, so that this procedure operates on the entire arg, and not just on a part of it.
See also:
- rotateLeft proc for a version which rotates a range
- rotatedLeft proc for a version which returns a seq[T]
Example:
var a = [1, 2, 3, 4, 5] a.rotateLeft(2) assert a == [3, 4, 5, 1, 2] a.rotateLeft(4) assert a == [2, 3, 4, 5, 1] a.rotateLeft(-6) assert a == [1, 2, 3, 4, 5]
Source Edit proc rotateLeft[T](arg: var openArray[T]; slice: HSlice[int, int]; dist: int): int {. discardable.}
-
Performs a left rotation on a range of elements. If you want to rotate right, use a negative dist. Specifically, rotateLeft rotates the elements at slice by dist positions.
The element at index slice.a + dist will be at index slice.a.
The element at index slice.b will be at slice.a + dist - 1.
The element at index slice.a will be at slice.b + 1 - dist.
The element at index slice.a + dist - 1 will be at slice.b.Elements outside of slice will be left unchanged. The time complexity is linear to slice.b - slice.a + 1. If an invalid range (HSlice) is passed, it raises IndexDefect.
- slice
- The indices of the element range that should be rotated.
- dist
- The distance in amount of elements that the data should be rotated. Can be negative, can be any number.
See also:
- rotateLeft proc for a version which rotates the whole container
- rotatedLeft proc for a version which returns a seq[T]
Example:
var a = [0, 1, 2, 3, 4, 5] a.rotateLeft(1 .. 4, 3) assert a == [0, 4, 1, 2, 3, 5] a.rotateLeft(1 .. 4, 3) assert a == [0, 3, 4, 1, 2, 5] a.rotateLeft(1 .. 4, -3) assert a == [0, 4, 1, 2, 3, 5] doAssertRaises(IndexDefect, a.rotateLeft(1 .. 7, 2))
Source Edit func sort[T](a: var openArray[T]; cmp: proc (x, y: T): int {.closure.}; order = SortOrder.Ascending) {.effectsOf: cmp.}
-
Default Nim sort (an implementation of merge sort). The sorting is guaranteed to be stable (that is, equal elements stay in the same order) and the worst case is guaranteed to be O(n log n). Sorts by cmp in the specified order.
The current implementation uses an iterative mergesort to achieve this. It uses a temporary sequence of length a.len div 2. If you do not wish to provide your own cmp, you may use system.cmp or instead call the overloaded version of sort, which uses system.cmp.
sort(myIntArray, system.cmp[int]) # do not use cmp[string] here as we want to use the specialized # overload: sort(myStrArray, system.cmp)
You can inline adhoc comparison procs with the do notation. Example:
people.sort do (x, y: Person) -> int: result = cmp(x.surname, y.surname) if result == 0: result = cmp(x.name, y.name)
See also:
- sort proc
- sorted proc sorted by cmp in the specified order
- sorted proc
- sortedByIt template
Example:
var d = ["boo", "fo", "barr", "qux"] proc myCmp(x, y: string): int = if x.len() > y.len() or x.len() == y.len(): 1 else: -1 sort(d, myCmp) assert d == ["fo", "qux", "boo", "barr"]
Source Edit proc sort[T](a: var openArray[T]; order = SortOrder.Ascending)
-
Shortcut version of sort that uses system.cmp[T] as the comparison function.
See also:
- sort func
- sorted proc sorted by cmp in the specified order
- sorted proc
- sortedByIt template
proc sorted[T](a: openArray[T]; cmp: proc (x, y: T): int {.closure.}; order = SortOrder.Ascending): seq[T] {.effectsOf: cmp.}
-
Returns a sorted by cmp in the specified order.
See also:
Example:
let a = [2, 3, 1, 5, 4] b = sorted(a, system.cmp[int]) c = sorted(a, system.cmp[int], Descending) d = sorted(["adam", "dande", "brian", "cat"], system.cmp[string]) assert b == @[1, 2, 3, 4, 5] assert c == @[5, 4, 3, 2, 1] assert d == @["adam", "brian", "cat", "dande"]
Source Edit proc sorted[T](a: openArray[T]; order = SortOrder.Ascending): seq[T]
-
Shortcut version of sorted that uses system.cmp[T] as the comparison function.
See also:
Example:
let a = [2, 3, 1, 5, 4] b = sorted(a) c = sorted(a, Descending) d = sorted(["adam", "dande", "brian", "cat"]) assert b == @[1, 2, 3, 4, 5] assert c == @[5, 4, 3, 2, 1] assert d == @["adam", "brian", "cat", "dande"]
Source Edit proc upperBound[T, K](a: openArray[T]; key: K; cmp: proc (x: T; k: K): int {.closure.}): int {. effectsOf: cmp.}
-
Returns the index of the first element in a that is greater than key, or last if no such element is found. In other words if you have a sorted sequence and you call insert(thing, elm, upperBound(thing, elm)) the sequence will still be sorted. Assumes that a is sorted according to cmp.
If an invalid range is passed, it raises IndexDefect.
This version uses cmp to compare the elements. The expected return values are the same as those of system.cmp.
See also:
- lowerBound proc sorted by cmp in the specified order
- lowerBound proc
Example:
var arr = @[1, 2, 3, 5, 6, 7, 8, 9] assert arr.upperBound(2, system.cmp[int]) == 2 assert arr.upperBound(3, system.cmp[int]) == 3 assert arr.upperBound(4, system.cmp[int]) == 3 arr.insert(4, arr.upperBound(3, system.cmp[int])) assert arr == [1, 2, 3, 4, 5, 6, 7, 8, 9]
Source Edit proc upperBound[T](a: openArray[T]; key: T): int
-
Returns the index of the first element in a that is greater than key, or last if no such element is found. In other words if you have a sorted sequence and you call insert(thing, elm, upperBound(thing, elm)) the sequence will still be sorted. Assumes that a is sorted.
This version uses the default comparison function cmp.
See also:
- lowerBound proc sorted by cmp in the specified order
- lowerBound proc
Templates
template sortedByIt(seq1, op: untyped): untyped
-
Convenience template around the sorted proc to reduce typing.
The template injects the it variable which you can use directly in an expression.
Because the underlying cmp() is defined for tuples you can also do a nested sort.
See also:
- sort func
- sort proc
- sorted proc sorted by cmp in the specified order
- sorted proc
Example:
type Person = tuple[name: string, age: int] var p1: Person = (name: "p1", age: 60) p2: Person = (name: "p2", age: 20) p3: Person = (name: "p3", age: 30) p4: Person = (name: "p4", age: 30) people = @[p1, p2, p4, p3] assert people.sortedByIt(it.name) == @[(name: "p1", age: 60), (name: "p2", age: 20), (name: "p3", age: 30), (name: "p4", age: 30)] # Nested sort assert people.sortedByIt((it.age, it.name)) == @[(name: "p2", age: 20), (name: "p3", age: 30), (name: "p4", age: 30), (name: "p1", age: 60)]
Source Edit